octahedral void
Asked by adilkhan | 13th Jul, 2010, 06:36: PM
As seen from the figure ABC is a right angled triangle. The centre of void is A.
Applying Pythagoras theorem we have
BC2 = AB2 + AC2
(2R)2 = (R + r)2 + (R + r)2
4R2 = 2(R + r)2
(√2 R)2 = (r + R)2
√2 R = r + R
r = √2 R - R
r = R(√2 - 1)
r = R(1.414 - 1)
r = .414R
Answered by | 20th Jul, 2010, 05:33: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change