obtain all zeroes of polynomial f(x)=2x4+x3-14x2-19x-6 , if two of its zero are -2 and -1.

First, given zeroes are -2 and -1

Thus factors = (x+2) and (x+1)

solve them, we get = x² + 3x+2

Now divide f(x) by x²+3x+2

On dividing, q(x) = 2x²-5x-3

Now  split the middle term and you 'll get two values --> (2x+3) and (x-1)

(2x+3)---> x=-3/2

(x-1)----> x= 1

Thus, the four Zeroes are 1, -1, -2 and -3/2