O is the point of intersection of the diagonals AC and BD of a trapezium ABCD with AB  DC. Through O, a line segment PQ is drawn parallel to AB meeting AD in P and BC in Q. Prove that PO = QO.

Asked by Vivek Menon | 17th Sep, 2013, 09:52: PM

Expert Answer:

Answered by  | 18th Sep, 2013, 09:16: AM

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