numerical

Asked by manu p.prakash | 14th Apr, 2011, 03:13: AM

Expert Answer:

Ans-
 
Since -q is moving around a charge +q along a circular path of radius r, therefore acceleration will be towards the center and has a magnitude  where v is the constant speed along a circle of radius r., from Newton,s law,
 
 
Therefore Time period will be
 
 
 
Hence shown

Answered by  | 16th Apr, 2011, 01:53: AM

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