numerical
Asked by manu p.prakash | 14th Apr, 2011, 03:13: AM
Expert Answer:
Ans-
Since -q is moving around a charge +q along a circular path of radius r, therefore acceleration will be towards the center and has a magnitude 
where v is the constant speed along a circle of radius r., from Newton,s law,
Therefore Time period will be
Hence shown
where v is the constant speed along a circle of radius r., from Newton,s law,Answered by | 16th Apr, 2011, 01:53: AM
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