CBSE Class 12-science Answered
Dear Student
The ans wer is T( R2-R1)
Details fallows
Say there are N0 atoms of radioacctive element initially.
it is given that it's mean life time =T
Number of radioactive atoms remained after t time N(t) = N0 e-t/T
Radioactivity at a given time t R = dN(t)/dt = - N(t)/T (" _ " sign denotes decrease)
R=N0 e-t/T / T
R1 = N0 e-T1/T / T ==>e-T1/T = R1 T /N0 ----------------(1)
R2 = N0 e-T1/T / T ==> e-T1/T=R2 T/N0-----------------(2)
N(T1) = N0 e-T1/T
N(T2) = N0 e-T2/T
Number of atoms that have disintegrated in time (T2 - T1) is dN = N(T1) - N(T2)
=N0( e-T1/T - e-T2/T )
Substitute (1),(2) in the above equation
dN=N0 X [ ( T/N0) ( R2-R1) ] = T( R2-R1)
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Team
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