numerical

Asked by pratibhakohli | 4th Jul, 2010, 08:19: PM

Expert Answer:

Average speed is given by = total distance covered/ total time taken
 
Let the object covers a total distance S
Then time taken to cover first half of the distance = S/2u
&, time taken to cover first half of the distance = S/2v
 
Therefore average speed is given by Vavg.= S/(S/2u + S/2v)
Vavg. = 1/[(u+v)/2uv]
i.e., Vavg. = 2uv/u+v
 
Hope this helps.

Answered by  | 16th Jul, 2010, 03:46: PM

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