CBSE Class 11-science Answered
Numerical
Asked by KANIKAKHARBANDA | 03 Jan, 2010, 01:18: PM
Expert Answer
Since the units of the distance between earth and moon is 3.8x105 km
The centripetal force required for circular motion is provided by the gravitational force between earth and moon.
mV2/r = GMm/r2
V = (GM/r)1/2
= (6.67x10-11x6.1x1024)/(3.8x108))1/2 = 1.06 x 103 m/s
The speed of moon = 1.06 km/s
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Answered by | 03 Jan, 2010, 02:17: PM
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