Asked by 24-02-1994 | 15th Jun, 2009, 08:35: AM
WE KNOW THAT, P = V2 / R
so, R = V 2 / P
= 220 x 220 / 100
= 484 ohm.
Hence, the resistance of the bulb is 484 ohm.
Now, let P1 be the power consumed at 110 volt ( = V1, say )
Then, P1 = V12 / R
so, P1 = 110 x 110 / 484
= 25 watt.
Answered by | 15th Jun, 2009, 12:05: PM
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