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CBSE Class 11-science Answered

numerical question
Asked by fathima12 | 29 Jun, 2011, 02:45: AM
answered-by-expert Expert Answer
Let us assume that the total no. of candidates appearing in the exam is 100.
Let us take U as the total no. of candidates in the exam
                 A be the no. of candidates failing in English
          and  B be the no. of candidates failing in Science.
 
Given,  n ( A ) = 56% of 100 = 56
           n ( B ) = 48% of 100 = 48
        
By set theory, we get
        
 
So, number of students passing in both the papers = n ( shaded portion )
                                                                        = n ( U ) - n ( A U B )
                                                                        = 100 - 86 = 14
 
Hence, required percentage = 14%
 
 
Answered by | 29 Jun, 2011, 04:18: PM

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