NUMERICAL QUESTION BASED ON THE MOTION UNDER GRAVITY
Asked by | 4th Dec, 2008, 03:19: PM
Take upward direction as positive and downward direction as negative.
Let height of tower be h and time of fall be t.
Either use formula for distance travelled in the nth second or find velocity at the end of t-1 seconds and use this as initial velocity for last one second of its fall.
As the body falls through 60.1m so it will have a negative sign, acceleration is also in the downward direction so it is negative.
S_n = u +1/2a(2n-1)
-60.1 = 0 +1/2(-9.8)(2n-1)
Solve for n.
Answered by | 6th Dec, 2008, 11:11: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number