NUMERICAL QUESTION BASED ON THE MOTION UNDER GRAVITY

Asked by  | 4th Dec, 2008, 03:19: PM

Expert Answer:

Take upward direction as positive and downward direction as negative.

Let height of tower be h and time of fall be t.

Either use formula for distance travelled in the nth second or find velocity at the end of t-1 seconds and use this as initial velocity for last one second of its fall.

As the body falls through 60.1m so it will have a negative sign, acceleration is also in the downward direction so it is negative.

S_n = u +1/2a(2n-1)

-60.1 = 0 +1/2(-9.8)(2n-1)

Solve for n.

Answered by  | 6th Dec, 2008, 11:11: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.