numerical problem
Asked by
| 13th Sep, 2008,
09:50: AM
Expert Answer:
Distance travelled in 0.5 s,s1 =20(0.5)=10 m
Remaining distance,s2 =100-s1 =90 m
Now,a=(v2 -u2 )/2s2 =400/180=2.22 ms-2
Answered by
| 13th Sep, 2008,
09:35: PM
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