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CBSE Class 11-science Answered

numerical problem
Asked by | 13 Sep, 2008, 09:50: AM
answered-by-expert Expert Answer

Distance travelled in 0.5 s,s1 =20(0.5)=10 m

Remaining distance,s2 =100-s1 =90 m

Now,a=(v2 -u2 )/2s2  =400/180=2.22 ms-2

Answered by | 13 Sep, 2008, 09:35: PM

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