CBSE Class 11-science Answered
NUMERICAL PROBLEM BASED ON MOTION WITH UNIFORM ACCELERATION
Asked by | 01 Dec, 2008, 05:30: PM
Expert Answer
The first quarter S = 100m.
u=0
t=10s
S=ut+1/2 at2 : 100 = 1/2 x a x (10)2
We find that the acceleration produced during the first 100 m = 2m/s2 .
The final velocity at the end of the 10th sec is : v= u +at →v=2x10 = 20m/s.
The rest 300 m is travelled at the speed of 20m/s.Hence the time taken is 300/20 = 15s.
Hence the total time taken is 10+15 = 25sec.
Answered by | 02 Dec, 2008, 08:34: PM
Concept Videos
CBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by dhanapolla | 28 Jan, 2024, 10:40: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by santoshyadav6673633 | 26 Jan, 2024, 04:55: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by manjusrihalder395 | 07 Jan, 2024, 09:55: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rahmanshah8572 | 29 Dec, 2023, 08:41: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by klvnsnthl | 25 Dec, 2023, 07:50: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by pothulasubbarayudu | 25 Dec, 2023, 06:58: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by neerajchaurasiya651 | 10 Dec, 2023, 09:32: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by debasishbarik2006 | 17 Nov, 2023, 07:03: PM
ANSWERED BY EXPERT