Numerical on solutions

Let amount of Na₂CO₃be’x’,NaHCO₃ will be 1-x

Since no of moles of both are equal

So,

         x              1-x

     ------ =        ------ =84x =106-106x

106                          84

 

190x =106

      106

x =------- =0.5578g

       190                 

 

1-x = 1-0.5578

       =0.4422

                  0.5578

n _{Na2CO3 =} ----------   =0.00526

                  106

 

 

                0.4422

n _{NaHCO3 =} ----------   =0.00526

                  84

 

Na₂CO₃ +HCl              2NaCl +H₂O +CO₂

 

 

 

NaHCO₃ +HCl              NaCl +H₂O +CO₂

 

M1V1 = 2M2V2+M3V3 = 2 X.00526+.00526

          .01578

V1 =------------ =0.1578L

              0.1