Numerical on solutions

Asked by  | 3rd May, 2008, 12:00: PM

Expert Answer:

Let amount of Na2CO3be’x’,NaHCO3 will be 1-x
Since no of moles of both are equal
So,
         x              1-x
     ------ =        ------ =84x =106-106x
106                          84
 
190x =106
      106
x =------- =0.5578g
       190                 
 
1-x = 1-0.5578
       =0.4422
                  0.5578
n Na2CO3 = ----------   =0.00526
                  106
 
 
                0.4422
n NaHCO3 = ----------   =0.00526
                  84
 
Na2CO+HCl              2NaCl +H2O +CO2
 
 
 
NaHCO+HCl              NaCl +H2O +CO2
 
M1V1 = 2M2V2+M3V3 = 2 X.00526+.00526
          .01578
V1 =------------ =0.1578L
              0.1

                                                                     

Answered by  | 7th Jul, 2008, 09:59: AM

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