CBSE Class 11-science Answered
Numerical involving Surface Tension...
Asked by RACHIT_MAHAAN | 03 Feb, 2011, 05:13: PM
Expert Answer
Dear student,
sigma=73X10^-7, h=20X10^-2,g=9.8m/s^2
Excess pressure at depth h, p = h X ro X g= 196000X10^-2 = 1960 N/m^2
In the equilibrium position, R = 2 X 73X10-7/1960 = 0.075X 10^-7m
Hope this helps.
Thanking you
Team
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Answered by | 04 Feb, 2011, 01:14: PM
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