CBSE Class 10 Answered
number system A.P.solve this question please
Asked by | 26 Mar, 2009, 08:59: AM
Expert Answer
Let the digits be x,-d,x,x+d at units ,tens and hundredth place respecticvely.
THEIR SUM, x-d+x+x+d=15
x=5
Now difference of two numbers,
(x+d)*100+x*10+(x-d)-(x-d)*100-x*10-(x+d)=594
99*(5+d)-99*(5-d)=594
99*2*d=594
d=3
Henc the number is : 852
Answered by | 28 Mar, 2009, 02:49: PM
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