number of the students left in the school auditorium in batches of 30 each The initial strength being 500. Can we say situation form an AP. Q2 for the given AP show that Ap+Ap+2q=2Ap+q Q3 find 31st and 42nd terms of the sequence defined by An= 0 if n is even 1 if n is odd

We would request you to please ask one question at a time. The answer to your first question is as follows:

 

The given situation forms an AP, if we look at the number of students left in the audotorium after when each batch went out.

 

In that case, the AP would be:

500, 470, 440, 410, ...

 

Here, first term = 500

common difference = -30