CBSE Class 10 Answered
not able to do
Asked by | 11 Feb, 2010, 06:12: PM
Expert Answer
Let length, width of the f ield are L,B,
Area =LB
a) (L+3) (B-2)= LB+4
LB+3B-2L-6=LB+4
3B-2L-10=0----(1)
b)(L-2)(B+1)= LB-1
LB-2B+L-2=LB-1
-2B+L-1=0-----(2)
2X(1) + 3X(2) ===> -4L-20+3L-3=0==> -L=-23
Sub stitute L in Eqn (1)===> B=-12
These are practicle solutions for length. But satis fies the problem
Regards
Team Topperlearning
Answered by | 11 Feb, 2010, 07:38: PM
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