no of solutions of eq=x^3+x^2+4x+2sinx=0 in 0less than equal to x less than = to pie

Asked by Amit Adhikari | 17th Jul, 2011, 12:00: AM

Expert Answer:

No of solution of the equation is only 1;
i.e  x=0; is the only solution for the equation.
because
2sinx=
and there is no value of x in 0 to  which makes sinx ,-ve.as RHS is -ve in 0 to .

Answered by  | 17th Jul, 2011, 09:39: PM

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