no. of moles of hydroxide ions in 0.3L of 0.005M solution of Ba(OH)2 is:
 

Asked by Anju Sharma | 1st Jun, 2014, 12:49: PM

Expert Answer:

0.3 L of 0.005 M Ba(OH)2 solution = 0.005 × 0.3 mol

= 0.0015 mol Ba(OH)2

=0.003 mol OH - ....Ans

Answered by Hanisha Vyas | 2nd Jun, 2014, 03:55: PM