Net electric flux
Asked by nca_sumeet | 25th Jun, 2009, 08:51: AM
Use Gauss's law,
1/ Since the charge is placed at the centre of one of the faces of the cube, there is no closed surface.
2/ To enclose the charge in a closed surface, assume that the another cube of same dimension has been stuck to the face, which carries the charge at it's centre.
3/ Now the first cube contributes 5 equal areas to the enclosing surface and second cube also contributes 5 equal areas. One equal area is the area of a face of the cube.
4/ The net electric flux is therefore q/ε0, but it's through 10 equal cube face area.
5/ Hence the electric flux through one face is q/(10ε0)
Answered by | 1st Aug, 2009, 03:35: PM
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