CBSE Class 9 Answered
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Asked by | 16 Feb, 2009, 03:28: PM
Expert Answer
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EA = AB = BF (Given)
Now AB = BC = CD = DA (sides of a rhombus)
BC = BF
⇒ 
BFC = BCF (angle opposite to equal side)
Similarly,
⇒ AED = ADE (angle opposite to equal side)
ABC = BFC +BCF (exterior angle)
= 2BFC
DAB= ADE +AED (exterior angle)
= 2AED
2AED + 2BFC= 1800 (composite pairs)
AED + BFC= 900
Now, In 
AFG
AED + BFC + EGF= 1800
⇒EGF= 900
Answered by | 17 Feb, 2009, 11:38: AM
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