CBSE Class 9 Answered
EA = AB = BF (Given)
Now AB = BC = CD = DA (sides of a rhombus)
BC = BF
⇒ BFC = BCF (angle opposite to equal side)
⇒ AED = ADE (angle opposite to equal side)
ABC = BFC +BCF (exterior angle)
DAB= ADE +AED (exterior angle)
2AED + 2BFC= 1800 (composite pairs)
AED + BFC= 900
Now, In AFG
AED + BFC + EGF= 1800
This video explains the congruence criteria of triangles through SAS and AS...
Establish the relation between equal sides and angles in a triangle. Apply...
This video explains the proof of congruence of right triangles and discover...
Find the sum of the interior angles of a triangle. Establish the relation ...
Relation between the length and measure of its opposite angle in a triangle...