ncert textbook question
Asked by ritamkumar | 10th Mar, 2010, 03:48: AM
Velocity of truck after 10 sec = 2x10 = 20 m/s2
When stone is released, it'll also have the same velocity. So the stone has a horizontal velocity of 20 m/s2
Time required to reach ground = (2h/g) = (12/9.8) = 1.11 sec.
So it'll reach ground at 11.11 sec.
Horizontal velocity remains unchanged, Vx = 20.
Vertical velocity = ut+0.5gt2 = 0.5x9.8x12 = 4.9 m/s2
Velocity of stone = (Vx2+Vy2) =(202+4.92) = 20.6 m/s2 and an angle tan-1(4.9/20) with the horizontal.
The acceleration will always be g = 9.8 m/s2
Answered by | 10th Mar, 2010, 09:40: AM
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