CBSE Class 11-science Answered
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Asked by Vipulgautam050 | 26 Aug, 2021, 08:57: AM
It is assumed that ' find x ' means to find the x-coordinate of particle-A

We are given that speed vA of particle-A when angular displacement θ = (π/6) as

Angular speed ωA of particle-A is

Whn the system of light rod of length r and particle-A starts from rest ,
angular velocity ωA when the angular displacement is θ is determined from kinematics as

where α is angular acceleration
Using eqn.(2) , above expression is written as

Above expression is simplified as

Angular acceleration α is determined using Newtons law to the rotational motion of system
that consists of rod and particl-A about the pivot point O .
τ = r × T × sin [ (π/4) + (θ/2) ] = I × α
where T is tension force that is giving torque τ and I is moment of inertia
r × T × sin [ (π/4) + (θ/2) ] = ( mA r2 ) × α ............................ (5)
where mA is mass of particle-A
If we apply Newton's law of motion to the block-B, then we have
mB g - T = mB a
T = mB ( g - a ) = mB
Answered by Thiyagarajan K | 26 Aug, 2021, 07:42: PM
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