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ICSE Class 9 Answered

 Find the length of seconds pendulum at a place where g = 10 m/s2 ?
Asked by Vikas | 28 May, 2018, 02:16: PM
answered-by-expert Expert Answer
The time required for one oscillation by seconds pendulum is 2 seconds.
T= 2 s
T equals 2 pi square root of l over g end root
l minus space l e n g t h space o f space p e n d u l u m
T minus space T i m e space p e r i o d
g minus space a c c e l e r a t i o n space d u e space t o space g r a v i t y

T h u s comma space T squared equals 4 pi squared l over g
rightwards double arrow l equals fraction numerator T squared g over denominator 4 pi squared end fraction space equals space fraction numerator 2 squared cross times 10 over denominator 4 cross times 3.14 squared end fraction equals space fraction numerator 40 over denominator 39.43 end fraction equals space 1.01 space m
Answered by Shiwani Sawant | 28 May, 2018, 03:07: PM
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