In the above reaction,what is the equivalent weight of NH3 and H2 and N2?
Asked by pb_ckt | 19th May, 2019, 11:59: PM
In formation of ammonia-
Oxidation state of N in N2 =0
Oxidation state of N in NH3 =-3
change in oxidation number of N in N2 in formation of NH3 =3
For 2 N atom = 6
So equivalent weight of N2 =28/6=14/3 g(molecular weight of N2 =28 g)
Equivalent weight of NH3= 17/3 g (molecular weight of NH3 =17 g)
Oxidation number change in H is =1 ( from 0 to +1)
so for two H atom in H2 =2
It means, equivalent weight of H2 = 2/1=2 g
Answered by Ravi | 20th May, 2019, 11:30: AM
- 50 ml of 0.1 (M) H2SO4 is mixed with 150 ml of 0.2 (M) NaOH solution, the resulting solution is (A) Acidic, (N/5) (B) Basic, (N/5) (C) Basic, 0.075 (M) (D) Basic,(N/10)
- How is Meq (miliequivalent) and g-eq (gram equivalent) different?
- pls explain
- what is mean by molar volume of gas
- When 50 ml of HCl reacts With 10gm of CaCO3,Normality of solution is?
- 0.5 moles of H2O contain how many molecules
- question of chemistry in image attached below.
- If 1 g of contains x atoms, what will be the number of atoms in 1 g of magnesium? (C=12 u, Mg= 24 u)
- 3.2 g of Sulphur DIoxide present in the flask. Calculate the moles of Sulphur DIoxide present in the flask
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number