my question is

Asked by 100.akash | 13th Sep, 2008, 12:37: PM

Expert Answer:

any point O which is equidistant from A and C will lie on perpendicular bisector of AC.

it is a property of rhombus that its diagonal intersect each other at right angle and bisects each other.

i.e. bisector of AC passes through B and D.

so point O ,B and D lie on a line or OBD is a straight line.

Answered by  | 13th Sep, 2008, 06:54: PM

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