my question is
Asked by 100.akash | 13th Sep, 2008, 12:37: PM
Expert Answer:
any point O which is equidistant from A and C will lie on perpendicular bisector of AC.
it is a property of rhombus that its diagonal intersect each other at right angle and bisects each other.
i.e. bisector of AC passes through B and D.
so point O ,B and D lie on a line or OBD is a straight line.
Answered by | 13th Sep, 2008, 06:54: PM
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