My exam is tomorrow, please answer Fast . Thanks in advance ..
In NCERT TB pg 117 ,right side, 1st para , it has been given that in sp hybridisation of BeCl2 , "each of the sp hybridized orbital overlaps with the 2p orbital of chlorine axially and forms two Be-Cl sigma bonds . "
but , the elect. Config of chlorine is 1s2 2s2 2p6 3s2 3p5 . As per this , Be has to overlap axially with 3p orbital of chlorine . It cannot overlap with 2p as it it already filled . But the textbook has mentions that it overlaps with 2p .... Plz explain this .... Thanks in advance .
Asked by Saravanan | 19th Jun, 2014, 04:57: PM
Expert Answer:
- Ground state electronic configuration of Be: 1s22s2
- In the excited state one of the 2s-electrons is promoted to vacant 2p orbital.
- One 2s and one 2p orbital gets hybridised to fom two sp hybridised orbitals.
- Each Be-Cl bond arises by axial overlap of a sp hybrid orbital on beryllium with a 3p orbital on chlorine.
- Ground state electronic configuration of Be: 1s22s2
- In the excited state one of the 2s-electrons is promoted to vacant 2p orbital.
- One 2s and one 2p orbital gets hybridised to fom two sp hybridised orbitals.
- Each Be-Cl bond arises by axial overlap of a sp hybrid orbital on beryllium with a 3p orbital on chlorine.
Answered by Vaibhav Chavan | 20th Jun, 2014, 11:55: AM
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