motion

Asked by  | 14th May, 2009, 12:22: PM

Expert Answer:

time taken in first case t1 = x / v1

time taken in second case t2 = x / v2

total time taken = t1 + t2 = x (v1 + v2) / v1 x v2

avg. velocity v = total displacement / total time

                         = (2 x) v1 v2 /( x) (v1 + v2)  = 2 v1 v2 / (v1 + v2)

Answered by  | 30th May, 2009, 11:16: AM

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