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CBSE Class 9 Answered

motion
Asked by | 20 Jul, 2009, 07:26: AM
answered-by-expert Expert Answer

The distance which the car travels before the brakes are applied = 25 x 5 = 125 m

We know, v = u + at

                so , a = v - u / t

                         = - 2.5 m/s2

                [ negative sign will indicate retardation ]

                                                     

The distance traveled by the car after applying the brakes = ut + at2 /2

                                                                                       = (25) (10) + ( -2.5) ( 10)2 /2

                                                                                        = 125 m 

Answered by | 20 Jul, 2009, 02:32: PM

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