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CBSE Class 11-science Answered

motion along a straight line
Asked by Janaki | 13 Oct, 2010, 09:03: PM
answered-by-expert Expert Answer
Dear Student,
 
x = a + bt2
 
v = dx/dt = 0 + 2bt = 2bt = 2 * 2.5 * t = 5t
v(@ t =0) = 5*0 = 0 m/s
v(@ t =4) = 5*4 = 20 m/s
 
Avg vel = Total distance / total time =[ x(@ t = 4) - x (@ t = 0)] / [4-0]
                                                   = [(a+b*42) - (a+b*0)] / 4
                                                   = [16b] / 4
                                                   = 16*2.5 / 4
                                                   = 10 m/s
 
Hope that satisfies your query.
 
Team
TopperLearning
Answered by | 14 Oct, 2010, 11:58: PM
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