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CBSE Class 12-science Answered

Mole fraction of glycerine in a solution of 36g of water and 46 g of glycerine
Asked by suryanshmishr | 05 Jul, 2019, 12:30: PM
answered-by-expert Expert Answer
Given:
 
Mass of water = 36gm
 
Mass of glycerine = 46 gm
 
Molar mass of watet= 18
 
Molar  mass of glycerine= 92
 
No. of moles of  water= 
equals 36 over 18

equals space 2 space moles
 
No. of moles of glycerine =
equals 46 over 92

equals space 0.5 space space mole
 
Total moles= 2+0.5
 
                     = 2.5 moles
 
Mole fraction of glycerine =
 
equals fraction numerator no. space of space moles space of space gycerine over denominator Total space no. space of space moles end fraction

equals fraction numerator 0.5 over denominator 2.5 end fraction

equals 0.2
 
Mole fraction of  water
 
equals fraction numerator 2 over denominator 2.5 end fraction

equals 0.8
 
Answered by Varsha | 07 Jul, 2019, 12:28: PM
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