Mole fraction of a solute in benzene(C6H6) is 0.2 then find molality of solute

Asked by Shaurya Pahal | 26th Oct, 2014, 07:06: PM

Expert Answer:

begin mathsize 12px style Let space the space solution space be space straight x space molal. space therefore space The space moles space of space benzene space present space in space 1000 straight g space of space benzene space equals space 1000 over 78 space equals space 120.82 space moles therefore space Mole space fraction space of space solute space equals space fraction numerator straight x over denominator straight x space plus space 12.82 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0.2 space space equals space fraction numerator straight x over denominator straight x space plus space 12.82 end fraction  Or space space space space space space 0.2 space cross times space straight x space plus space 0.2 space cross times 12.82 space equals space straight x space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 2.564 space equals space straight x space minus space 0.2 space straight x or space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 2.564 space equals space 0.8 space straight x therefore space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space bold x bold space bold space bold equals bold space bold 3 bold. bold 2 end style
 
Therefore, molality of solute = 3.2 moles

Answered by Hanisha Vyas | 27th Oct, 2014, 11:17: AM

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