Molar conductance values at infinite dilution of Na+ and Cl- ions are 50.11*10^-4Sm^2mol^-1 and 76.34*10^-4Sm^2mol^-1 respectively. Calculate the transport number of Na+ ion.
Asked by mrudulmahadev1311
| 22nd Aug, 2019,
07:47: AM
Expert Answer:
Given:
Molar conductance at infinite dilution;
λ+Na = 50.11×10−4 Sm2mol−1
λ+Cl = 76.34×10−4 Sm2mol−1
Molar conductance of NaCl is = λ+Na + λ+Cl
= 50.11×10−4 + 76.34×10−4
= 126.45×10−4 Sm2mol−1
Transport number of Na+
Answered by Varsha
| 22nd Aug, 2019,
12:32: PM
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