Molal enthalpy of fusion of water at 273 K is 6.02.Calculate molal depression constant of wat.er

Asked by Akshya Achu | 1st Jul, 2014, 09:13: PM

Expert Answer:

Kf = R x M x Tf2 / 1000 x ΔHf

= 2 x 18x (273)2 / 1000 x 6.02

= 445.688

Answered by Prachi Sawant | 2nd Jul, 2014, 11:42: AM