Minimum value of a trig. function

Asked by  | 5th Jul, 2009, 09:34: AM

Expert Answer:

f(θ)= | sin θ + cos θ + tan θ + cot θ + sec θ + cosec θ |

f(θ)= | sin θ + cos θ + tan θ + 1/tan θ + 1/cos θ + 1/sin θ |.

f(θ)= | 1 + sin2 θ + 1 + cos2 θ + 1 + tan2 θ |

f(θ)= | 4+ tan2 θ |

tan2 θ can't be negative and least value it can take is zero.

Hence the minimum value of given function is 4.

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Answered by  | 4th Sep, 2009, 09:31: AM

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