MID PTS THEOREM

Asked by  | 13th Sep, 2009, 06:57: AM

Expert Answer:

part i)

in the triangles FHC and HEB

EB=FC....since they are half parts of equal sides AB ,CD.

also

FC II EB

angle FCH= angle  HEB

angle CFH= angle HBE...(alt interior angles)

so triangles are cong by ASA rule.

part ii)

consider the quadrilaterlal AECF,

AE=CF....half parts of equal sides AB and CD

also

AE II  CF...since AB , CD are parallel.

so AECF is a parallelogram.

so

GF  II EH

and

GE  II HF

so GEHF  is also a parallelogram... both pairs of opp sides are parallel.

Answered by  | 13th Sep, 2009, 08:31: AM

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