MID PTS THEOREM
Asked by | 13th Sep, 2009, 06:57: AM
in the triangles FHC and HEB
EB=FC....since they are half parts of equal sides AB ,CD.
FC II EB
angle FCH= angle HEB
angle CFH= angle HBE...(alt interior angles)
so triangles are cong by ASA rule.
consider the quadrilaterlal AECF,
AE=CF....half parts of equal sides AB and CD
AE II CF...since AB , CD are parallel.
so AECF is a parallelogram.
GF II EH
GE II HF
so GEHF is also a parallelogram... both pairs of opp sides are parallel.
Answered by | 13th Sep, 2009, 08:31: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number