Mention the gamates produced from genotype AaBbCcDd?
Asked by hemanttkumarr | 2nd Jul, 2018, 08:44: PM
No.of possible gametes can be found through genotype by counting the no.of heterozygous or dissimilar allele pairs present in the genotype. These are denoted by 'n'.
No of possible genotypes = 2n
No. of allele pairs = 4 (Aa, Bb, Cc, Dd)
No. of gametes produced = 2n = 24 = 16
Therefore, a total of 16 gametes can be produced from the genotype AaBbCcDd.
Answered by Sheetal Kolte | 3rd Jul, 2018, 10:13: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number