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CBSE Class 10 Answered

MENSURATION
Asked by chahat | 06 Mar, 2009, 12:07: PM
Expert Answer

volume of metal in the conical hole=(1/3)*(22/7)*(3/2)*(3/2)*(8/9)=44/21

Volume of metal left in the cylinder= volume of the cylinder - volume of cone.

=(22/7)(3)*(3)*(5)-[44/21]

Find these quantities and take the required ratio.

Answered by | 06 Mar, 2009, 04:08: PM
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