Asked by chahat | 6th Mar, 2009, 12:07: PM

Expert Answer:

volume of metal in the conical hole=(1/3)*(22/7)*(3/2)*(3/2)*(8/9)=44/21 Volume of metal left in the cylinder= volume of the cylinder - volume of cone. =(22/7)(3)*(3)*(5)-[44/21] Find these quantities and take the required ratio.

Aswered by  | 6th Mar, 2009, 04:08: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.