CBSE Class 12-science Answered
F = q(v x B)
Proton's position vector = aj
Proton's initial velocity = vk
The magnetic field at proton's location, B = Bk = μ0ik/(2πa)
{Curl the right hand fingers around the conductor with thumb pointing in the direction of +x i.e. direction of current.
The curled fingers represent magnetic field lines, the tangent at proton's location points in the +z direction}
F = q(v x B) = +e(vk x Bk) = 0
Electron's position vector = -aj
Electron's initial velocity = vi
The magnetic field at proton's location, B = B(-k) = μ0i(-k)/(2πa)
F = q(v x B) = -e(vi x B(-k))
= -evBj
= -evμ0i j/(2πa)
The magnetic force on the proton is zero, while electron experiences a magnetic force in -y direction.
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