Asked by tangocharliee | 10th Nov, 2009, 11:43: PM
A non conducting disc means that the disc is not an electro magnet.
A charged disc rotating at constnt angular velocity is equivalent to a steady current in circular wire. We need to calculate this current to find the magnetic field. Let us consider any one cross-section of the wire and all charges must pass through this crosssection in one time period of revolution.
Hence current is:
I = q/T = q (ω / 2π)
Magnetic field due to steady current in a circular wire is:
B = µoI / 2R
Substituting for current , we have,
B = µoqω / 4πR
Hope this helped.
Answered by | 17th Dec, 2009, 11:54: AM
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