L.P.G cylinder can withstand a pressure of 14.9 atmosphere.The pressure gauge of the cylinder indicates 12 atmosphere at 27°C.Due to a sudden fire in the building the temperature rises.At what temperature will the cylinder explode.

Asked by saif | 14th Mar, 2017, 11:08: PM

Expert Answer:

Given:

P1 = 12 atm

T1 = 300K

P2 =14.9 atm

Solution:

P1/T1 = P2/T2

Hence 12/300 = 14.9/T2

T2 = 372.5K

 

Answered by Vaibhav Chavan | 15th Mar, 2017, 10:12: AM