CBSE Class 11-science Answered
Logarithms
Asked by Kirandoon | 16 Dec, 2008, 10:49: PM
Expert Answer
this can be written as log{ (16/15)7 (25/24)5 (80/81)3 }
= log { (2*2*2*2)7(5*5)5 (3*3*3*3)3 / (3*5)7 (2*2*2*3)5 (2*2*2*2*5)3 }
= log{ (2)28 (5)10 (3)12 / (2)27(3)12 (5)10 }
=log (2)
Answered by | 16 Dec, 2008, 11:40: PM
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