CBSE Class 10 Answered
linear equations
Asked by suchet_r | 05 Oct, 2009, 08:34: PM
Expert Answer
Let his original speed be x and time required with this speed be T.
Then xT = 108,
(x +2)(T - 4.5) = 108
xT - 4.5x + 2T - 9 = 108 = xT
2T - 4.5x = 9
2(108/x) - 4.5x = 9
4.5x2 + 9x - 216 = 0
x = [-9 ±
(81 + 3888)]/9
x = ( -9 + 63)/9 = 6 km/hr.
Regards,
Team,
TopperLearning.
Answered by | 05 Oct, 2009, 09:38: PM
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