lim (a+h)2 sin (a+h) -a2 sin a / h

Asked by  | 11th Jun, 2008, 08:43: PM

Expert Answer:

Using sin(a+h)=sinacosh+cosasinh

lim(h-->0)       (   (a+h)2 sin (a+h) -a2 sin a)  /  h   = lim(h-->0)   (   (a+h)2sinacosh+(a+h)2cosasinh -a2 sin a ) /   h   

Siplifying and using sinh=h-h3/3! ...

The limit is equal to a2cosa.

Answered by  | 10th Dec, 2008, 09:27: PM

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