NEET Class neet Answered
Light of wavelength 589.3nm is incident normally on a slit of width 0.1nm . What will be angular width of the central diffraction maximum at a distance of 1m from slit. a)0.68 degree b)1.02 degree c)0.34 degree d)none of these
Asked by vyshnaviudayakumar | 17 May, 2021, 03:34: AM
Expert Answer
For single slit diffraction , we have ,
a sinθ = λ
where a is slit width , θ is angular width of central maximum and λ is wavelength of light used .
sinθ = λ / a = 589.3 nm / 0.1 nm = 5.893 × 10-6
if θ << 1 , then sinθ = θ , hence θ = 5.893 × 10-6 rad = 5.893 × 10-6 × ( 180 / π ) = 3.376 × 10-4 degree
Hence answer :- (d) none of these
Answered by Thiyagarajan K | 17 May, 2021, 08:16: AM
NEET neet - Physics
Asked by vyshnaviudayakumar | 17 May, 2021, 03:34: AM
ANSWERED BY EXPERTNEET neet - Physics
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