let (h,k) be a fixed point , where h>0,k>0. a straight line passing through this point cuts the posi
Asked by | 25th Mar, 2008, 09:40: AM
let a and b be the intercepts made by the line on x and y axis.
equation of line will be
the area of triangle made by this line will be (1/2)*a*b
since this line passes through (h,k). put it in that equation.then find the relation b/w a,b,h,k. replace b in terms of a,h,k in area expression. Then minimize it and find the value of a .
So min.area will occur when (h,k) is the middle point of the section of line intercepted b/w axis. in that case a=2h,b=2k
so min. area will be=2hk
Answered by | 10th Aug, 2008, 02:49: AM
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