let f(theta)=[1+(4sintheta/sin6theta)] [1+(4sin2theta/sin5theta)]

Asked by digbijaybehera008 | 15th Sep, 2021, 09:15: AM

Expert Answer:

Given: f(theta)=[1+(4sintheta/sin6theta)] [1+(4sin2theta/sin5theta)]
straight f open parentheses straight theta close parentheses equals open square brackets 1 plus fraction numerator 4 sinθ over denominator sin 6 straight theta end fraction close square brackets open square brackets 1 plus fraction numerator 4 sin 2 straight theta over denominator sin 5 straight theta end fraction close square brackets
rightwards double arrow straight f open parentheses straight pi over 7 close parentheses equals open square brackets 1 plus fraction numerator 4 sin begin display style straight pi over 7 end style over denominator sin begin display style fraction numerator 6 straight pi over denominator 7 end fraction end style end fraction close square brackets open square brackets 1 plus fraction numerator 4 sin begin display style fraction numerator 2 straight pi over denominator 7 end fraction end style over denominator sin begin display style fraction numerator 5 straight pi over denominator 7 end fraction end style end fraction close square brackets
rightwards double arrow straight f open parentheses straight pi over 7 close parentheses equals open square brackets 1 plus fraction numerator 4 sin begin display style straight pi over 7 end style over denominator sin begin display style open parentheses straight pi minus straight pi over 7 close parentheses end style end fraction close square brackets open square brackets 1 plus fraction numerator 4 sin begin display style fraction numerator 2 straight pi over denominator 7 end fraction end style over denominator sin begin display style open parentheses straight pi minus fraction numerator 2 straight pi over denominator 7 end fraction close parentheses end style end fraction close square brackets
rightwards double arrow straight f open parentheses straight pi over 7 close parentheses equals open square brackets 1 plus fraction numerator 4 sin begin display style straight pi over 7 end style over denominator sin begin display style straight pi over 7 end style end fraction close square brackets open square brackets 1 plus fraction numerator 4 sin begin display style fraction numerator 2 straight pi over denominator 7 end fraction end style over denominator sin begin display style fraction numerator 2 straight pi over denominator 7 end fraction end style end fraction close square brackets
rightwards double arrow straight f open parentheses straight pi over 7 close parentheses equals open square brackets 1 plus 4 close square brackets open square brackets 1 plus 4 close square brackets
rightwards double arrow straight f open parentheses straight pi over 7 close parentheses equals 25

Answered by Renu Varma | 23rd Sep, 2021, 01:36: PM

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