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let f:R->R be the function defined by f(x)=x^3+5.Then f^-1(x) is 
Asked by bhuvanshetty1340 | 03 Jul, 2020, 19:59: PM
answered-by-expert Expert Answer
f(x)=x3+5
Let y=f(x)
f-1(y) = x
x3+5 = y 
x3 = y - 5
x = (y - 5)1/3
f-1(y) = (y - 5)1/3
Hence, f-1(x) = (x - 5)1/3
Answered by Renu Varma | 04 Jul, 2020, 19:23: PM

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