lens and power
Asked by nishac
| 28th Dec, 2009,
11:35: AM
Focal length of convex lens, f1 = 18 cm = 0.18 m
Power of convex lens , P1 = 5.6 D
Focal length of concave lens, f2 = - 24 cm = - 0.24 m
Power of concave lens, P2 = - 4.2 D
Power of the combination, P = P1 + P2 = 5.6 - 4.2 = 1.4 D
Focal length of the combination , F = 1 / 1.4 = 0.7 m
Hence, the combination will act as convex lens.
Answered by
| 4th Jan, 2010,
10:18: PM
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