L-4 QUADRATIC EQUATIONS (RD EX:4.9, Pg.4.9)

Asked by  | 28th May, 2008, 05:14: PM

Expert Answer:

x (x+1) = 306

x2 + x = 306

x2 + x - 306 = 0

x2 + 18x - 17x - 306 = 0

x(x+18) -17(x+18) = 0

(x+18)(x-17)

x = -18 , 17 (reject the negative value)

x = 17

x+1 = 18

 

Answered by  | 28th May, 2008, 09:56: PM

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